- 0
- 1
- -1
- -2

Option 1 : 0

**Given:**

3cosθ + 4sinθ = 5

**Calculation:**

⇒ 3cosθ + 4sinθ = 5

⇒ 9cos^{2}θ + 16sin^{2}θ + 24cosθ sinθ = 25 (By squaring the both side)

⇒ 9 × (1 - sin^{2}θ) + 16 × (1 - cos^{2}θ) + 24 × cosθ × sinθ = 25

⇒ 9sin^{2}θ - 24 cosθ × sinθ + 16 cos^{2}θ = 0

⇒ (3sinθ - 4cosθ)^{2} = 0

⇒ 3sinθ - 4cosθ = 0

**∴ The required result will be "0".**

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,18,09,936+ Students

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

[email protected]
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)