The yield strength for a mild steel specimen was found to be 250 N/mm^{2}. Taking a safety factor of 2, find out the working stress.

This question was previously asked in

PGCIL DT Civil 2018 Official Paper

- 250 N/mm2
- 125 N/mm2
- 500 N/mm2
- 150 N/mm2

Option 2 : 125 N/mm2

__Concept:__

Factor of safety (FOS) = Yield stress / Working stress

__Calculation:__

Given, FOS = 2

Yield strength = 250 N/mm2

FOS = Yield stress / Working stress

Working stress = 250 / 2 = 125 N/mm2

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